Matematika Sekolah Menengah Atas [+50]fungkomdiket f(x) = 3x + 4 dan g(x) = x² + 1 Tentukan:(fog)(x) = __(gof)(x) = __Jan spam​

kolestreichulv – May 10, 2023

[+50]fungkom

diket f(x) = 3x + 4 dan g(x) = x² + 1
Tentukan:
(fog)(x) = __
(gof)(x) = __


Jan spam​

Diketahui

f(x) = 3x + 4 dan g(x) = x² + 1

Ditanya

• (fog)(x)
• (gof)(x)

Jawab

(fog)(x) = f(g(x))

(fog)(x) = f(x² + 1)

(fog)(x) = 3(x² + 1) + 4

(fog)(x) = 3x² + 3 + 4

(fog)(x) = 3x² + 7

(gof)(x) = g(f(x))

(gof)(x) = g(3x + 4)

(gof)(x) = (3x + 4)² + 1

(gof)(x) = (3x + 4)(3x + 4) + 1

(gof)(x) = 9x² + 12x + 12x + 16 + 1

(gof)(x) = 9x² + 24x + 17

cmiiw

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